PC202019-08-11T06:24:00Z2019-08-11T06:24:00Z12293030485312001691535825162019-2020学年鲁科版必修1 5.2 力的分解 作业1、图中的大力士用绳子拉动汽车,绳中的拉力为F,绳与水平方向的夹角为H4sIAAAAAAAEC01Rv2/TUBD+zo4DcSOcUH6EChEHVJAQpKgDc10n/BiCIhKJjdSE19ZS4qRxCETq
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.若将F沿水平方向和竖直方向分解,则其竖直方向的分力为( )。iVBORw0KGgoAAAANSUhEUgAAATMAAABSCAYAAAA4hzMVAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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2、67.为了行车方便与安全,磨子桥引桥很长,坡度较小,其主要目的是( )。A. 减小过桥车辆受到的摩擦力B. 减小过桥车辆的重力C. 减小过桥车辆的重力沿引桥面向下的分力D. 减小过桥车辆对引桥桥面的压力3、如图所示,重为H4sIAAAAAAAEC11RPW8TQRB9e2cb7BjdmQ8RogifQZAGHIcCifJim4/CloUt0SAZY5bkJH/JZwLu
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TkSuQmCC
A. 小球不一定受摩擦力的作用B. 小球受摩擦力的方向一定沿杆向上,大小为H4sIAAAAAAAEC11RPW8TQRB9u/4AO5bO5ishQvgMAhpwEAL3l7P5KGxZ2BIVOl/MEU6yz5bPBNyZ
JkIIyUR09PwCWopUafgoaNJQIdEj6zokzJuLC8Te7c6bN7uzs28Ovxy8Qzw6el/pjMAPDxUIErcU
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fUBUl5NlvIoPSJ9zP9Z4k3RCbqTCjCRogb8giR8AgAIAAA==
C. 杆对小球的弹力方向垂直于杆向下,大小为H4sIAAAAAAAEC3VSPYgTQRR+M5tEsxfc5FSMh5iNh2fj5UQOOez2kvhTJAQTsBGSNbeeC0k2ZONp
utiEQ4QIioWt2NrYWgSEazzF7horQQQrCVscCq7f240gom9/5ptv3rxv3nuz927nGQXWUCZCxhm+
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D. 杆对小球的弹力方向垂直于杆向上,大小为H4sIAAAAAAAEC11Rv2/TQBR+d04CSS3ZKSBKVREHBCwlpRmQGF0n/BgSRSQSC5Ix4WgtJU4Upy3Z
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4、为了行车方便与安全,高大的桥要造很长的引桥,其主要目的是( )。A. 增大过桥车辆受到的摩擦力B. 减小过桥车辆的重力C. 增大过桥车辆的重力平行于引桥面向上的分力D. 减小过桥车辆的重力平行于引桥面向下的分力5、如图所示,将绳子的一端系在汽车上,另一端系在等高的树干上,两端点间绳长为10 m.用300 N的拉力把水平绳子的中点往下拉离原位置0.5 m,不考虑绳子的重力和绳子的伸长量,则绳子作用在汽车上的力的大小为( )。iVBORw0KGgoAAAANSUhEUgAAA3kAAAGbCAMAAABOPalHAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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SUVORK5CYIJ=
A. 1 500 N B. 6 000 NC. 300 N D. 1 500iVBORw0KGgoAAAANSUhEUgAAAB8AAAAqCAYAAABLGYAnAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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N6、一个竖直向下的180N的力分解为两个分力,一个分力在水平方向上并等于240N,另一个分力的大小为( )。A. 60N B. 260N C. 300N D. 420N7、生活中离不开刀刃劈物体,如斧子、砍刀、菜刀、铡刀等,为研究问题方便,我们建立这样一个物理模型:把此类刀刃的横截面等效为一个顶角为θ的等腰三角形,若以大小为F力劈开物体,则刀刃劈物体时对物体侧向推力的大小为( )。A. H4sIAAAAAAAEC6VTTWgTURCe93a3TdPIJk3FWqRNBO3FtpCDN6WbpLEeIsEERS8hxrVdSDZptpLm
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A. A B. B C. C D. D10、如图所示,重力为G的物体静止在倾角为α的斜面上,将重力G分解为垂直斜面向下的力F1和平行斜面向下的力F2,那么( ) ( )。iVBORw0KGgoAAAANSUhEUgAAAK0AAABmCAYAAAC5gBE0AAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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A. F1就是物体对斜面的压力B. 物体对斜面的压力方向与F1方向相同,大小为GsinαC. F2就是物体受到的静摩擦力D. 物体受到重力、斜面对物体的作用力是一对平衡力11、一体操运动员倒立并静止在水平地面上,下列图示姿势中,假设两手臂用力大小相等,那么沿手臂的力F最大的是( )。A. iVBORw0KGgoAAAANSUhEUgAAAEAAAAA9CAYAAAAd1W/BAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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12、力的合成和分解在生产和生活中有着重要的作用,下列说法中正确的是( )。A. 高大的桥要建很长的引桥,减小斜面的倾角,是为了减小汽车重力平行于桥面的分力,达到行车方便和安全的目的B. 幼儿园的滑梯很陡,是为了增加小孩滑滑梯时受到的重力,使小孩下滑得更快C. 运动员做引体向上(缓慢上升)动作时,双臂张开很大的角度时要比双臂竖直平行时学得手臂用力大,是因为张开手臂产生的合力增大的缘故D. 斜劈顶角越小越容易钉进物体,是因为斜劈顶角越小,劈面给物体的弱力越小13、如图所示,将一个大小为6N的力F沿相互垂直的x轴和y轴分解.已知力F与x轴的夹角H4sIAAAAAAAEC3VSPYgTURCeebsbzV5gE3/PIGbj4YlgckEhXcS9JP4UkWACFlfEvbh3LuTvsjGa
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,则力F在x轴上的分力F的大小为( )。iVBORw0KGgoAAAANSUhEUgAAAG8AAAB0CAYAAACL1Gw4AAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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C. Fsinθ D. Fcosθ18、在一些救援行动中,千斤顶发挥了很大作用.如图所示是剪式千斤顶,当摇动把手时,螺纹轴就能迫使千斤顶的上,两臂靠拢,从而将汽车顶起.当车轮刚被顶起时汽车对千斤顶的压力为1.0×105 N,此时千斤顶两臂间的夹角为120°,则下列判断错误的是( )。iVBORw0KGgoAAAANSUhEUgAAAJsAAACMCAYAAABrstuvAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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A. 此时两臂受到的压力大小均为1.0×105NB. 若继续摇动把手使两臂靠拢,两臂受到的压力将减小C. 此时千斤顶对汽车的支持力为1.0×105 N _D. 若继续摇动把手使两臂靠拢,两臂受到的压力将增大19、生活中的物理知识无处不在,如图所示是我们衣服上的拉链的一部分,在把拉链拉开的时候,我们可以看到有一个三角形的东西在两链中间运动,使很难直接分开的拉链容易地拉开,关于其中的物理原理以下说法中正确的是( )。iVBORw0KGgoAAAANSUhEUgAAAIoAAABMCAIAAAA9VLiaAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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A. 在拉开拉链的时候,三角形的物体增大了分开两拉链的力B. 拉开拉链的时候,三角形的物体只是为了将拉链分开并没有增大分开拉链的力C. 拉开拉链时,三角形的物体增大了分开拉链的力,但合上拉链时减小了合上的力D. 以上说法都不正确20、已知力F的一个分力F1跟F成θ角,F1大小未知,如图,则另一个分力F2的最小值为( )。iVBORw0KGgoAAAANSUhEUgAAAJEAAABUCAMAAAC1IyUWAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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C. H4sIAAAAAAAEC41SPWzTUBC+e3ZC41pyAkWUChEHBF1oWjEw13USYAiKSCQGhmCMKZYSJ41NIFso
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D. 无法判断参考答案1、答案:A将F分解为水平方向和竖直方向,根据平行四边形定则,竖直方向上分力H4sIAAAAAAAEC5VTz2sTURCeedkkdhvYRKvGWsxGaQWxKXjwIoGmSVcFI8EEPPQQY9zWhWSTZmNs
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,A正确.2、答案:CB、对车受力分析,受重力、支持力和阻力,物体重力不变,B错误;C、重力产生两个作用效果,使物体沿斜面下滑,使物体紧压斜面,设斜面倾角为θ,将重力按照作用效果正交分解,如图所示:iVBORw0KGgoAAAANSUhEUgAAAKoAAABlCAYAAADdyHjjAAAABGdBTUEAALGPC/xhBQAAAAlwSFlz
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F3u2NWK1pOmvNot3eDUjcSLHL8WC4qN+//335pTly0Sk/3lsf+dvab7Ahx4dfzXa0EkQaT4GXqhp
F3SxLrgktTQP/u9t/zSNTdujrfNk+l1BrZkZDou6iBeUQ7vWVV7Lvxmz2bbcOX9nzrfXmkr6qH1j
Zn6EzMYdyp2aiXZY2DHhQDpBqBnosHz6ovlX47jjkwuVKAMSW3Za1rgzShGsaT6CUDPiE9Zss+mP
y4nFqhbpzAU6CUItiA7lavOvgmaWQbkDDvVEW6Qg1DxEulsQuhJf9Zi2Typly66Y5r03Cd3Vxpj/
AzV5zuc53zmEAAAAAElFTkSuQmCC
由几何关系可得:平行斜面分量为G1=mgsinθ,由于引桥越长,坡角θ越小,G1越小,故C正确;A、D、θ变小,压力变大,故摩擦力变大,但增加摩擦不是目的,故A、D错误;故选C.名师点评:本题关键将重力正交分解后,根据平衡条件求解出压力和重力的下滑分量,然后对结果联系实际情况讨论即可判断.3、答案:B在沿斜面方向,重力的分力为H4sIAAAAAAAEC41Tz2sTQRR+M7uJyTa4ibYYi5iNol5sCh5yEANuk1Q9JASzID2lMa5xIbtJs2k0
t0ilFi8pCB68iuCf4MGDp1z8gXjpxZMiXkvYm2B8b7IlGiw47M68+WbefPPe+2bvw/A5iNYPAWdh
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Ll+r6KVR4rRe8hZUHby8d84brFTQiqpZHEYJ7eVIQSyJAKLqde+EN0B8sZKr5D36dDXCMHGMY8MS
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,则斜面对小球的摩擦力大小为H4sIAAAAAAAEC11RPY8SURQ97w2gsCQDfmTXjZFBozbKGqP0swN+FCAREisDI47rJDAQBlfp2GZj
bHBjZ+8vsLXYahs/CpttrExsrAyZzkQ8d5bC+Gbeu+ee+9599517+PngLeLR0ftKpwW+f6hAYNxU
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sdcHRHXRu4RX8QHpc/b7Gm+STsiNVJgRgxb4C8+CIFGAAgAA
,方向沿斜面向上,故A错误,B正确;对小球受力分析,小球一定受重力及拉力,将重力沿斜面和垂直于斜面进行分解可知,垂直于斜面上的分力H4sIAAAAAAAEC41Sz2sTQRR+M/mhSRc2qRFrEbNRVBCbggXbSw7bJEYPCbEJeEzWdY0L2WzIxmgu
EimU4CUFwYN3JSfJH+Chh5KL1ZPQi1AQRPAkYW+C8b3pBiUgOOy8/ebNm/e9efMdfhi/AjGqEnAW
ItgsMkDg22cAHN6K3QBaztABhBifTqcCJdlZz7fAEQifxIFXpQVcXQ7KIEFeaz8sd5sGQBEWPe8y
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RbzTYxc7u4sPjvwYtoLRxHs9TIdO4NRtZ219ozAdwh68xLnPD/C+M7YkzLMJuv9mY0CsP/AQXshj
9SHKWbWtNzzG/jAN2TwThjG6V6lr3bPr0PnkC5f635r/vNcxE5tjSo1SsafB73gnej16hTtMbTad
/M10msFVrIxmxnDMWkMp6abR0I1ryu2GnoQAg2AoU8qXbwA7dddsqPX6puaYetq+bxS1muFANDDf
9KjPKzcaSNuPWqbRoheBqD9fVrJP2i0NvEx/JQm+/3jwFZ/lZGL1yqSSGCRWcxW1OImfV4vuaVkF
N+tecgebFUQROY2/SVx5PQmjL4EO9Mq33DPuAP3LlUwl69KnyhLD9jGOA5vIUK8+XPtRUWEmpIbd
AJlx2M4B9++kIIXQwtDtGppnOhmbjIOmv0ZmnQJHMJqF9zdov0CJSE7U27DQstCIp5yIUBnAO1Lx
DtZzodR12oYFR6RJOpmE5+IAGenLklDMCtY7Uw7pBeA3mwERx54DAAA=
,小于拉力,故杆对球应有垂直向下的弹力,大小为H4sIAAAAAAAEC3VSTW8SURS97/EhTElmqBprY8pQo90ApSy0MWExBfxYQIiQdEkRp3USvsIgysbQ
DSFuMHHnrgt/gHsXs+rGjxg33bgyMW4NmRgTk+K5gIkxemfevPPOe/POfee+k3fHL2geAUeIIMMP
u4IAPE8EkaSj2awPXylAECMhp9PpDCXExQW3JAFmXEg6ggJLGF31qxSifLX7oNxvm0RJWl6wq4Qd
pkQaxg7QMZpzhmgICVYI8m6S0Tm5J27QJaCfcnCKDvGME+HktLLVMG29YD7S77Ya1SZ9OlmhwfNI
byAu914p+zEvlsWxWkOfUvAhP6Pk9laq4NCp0KRDH3HW30rfxT+UBCuV+o17rTr1fniVtdHX9n+U
BLHiNyiy2FyRjxJPa5I8R0DsyXVhtNt2/mYmI0jj7NCypm0dNPVSzTKbNTOm32nWEuQT5A9mS/ny
NRJnd62mUa/vVG2rlmndN4vVA9OmsO9vC8KeRaphX6b1sGOZHfaHwt58Wc897naqtNjpj038b96/
/YLiBKKbG5NKdBzdvFUxipPImlF0z6sGuTn3ijveqQBpagbdJKK/nCjgoiDAqrfdC+4Y/GolW8m5
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G2JeMY1wfRCv2e4hVNdLfbtrNijG94DrkaCn8x+wIPR5ZVapOJh5xTg7jl+NAKpFEgMAAA==
,故CD错误;故选B.4、答案:D对车受力分析,受重力、支持力和阻力,物体重力不变,重力产生两个作用效果,使物体沿斜面下滑,使物体紧压斜面,设斜面倾角为θ,将重力按照作用效果正交分解,如图:iVBORw0KGgoAAAANSUhEUgAAAKoAAABlCAYAAADdyHjjAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAJcEhZcwAADsEAAA7BAbiRa+0AABGcSURBVHhe7Z1LiB3FGsc7ihGJqLlJiFGJgpEk
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tSN5oLosYORzkOCvUlY9IR5bvyH04EptezAO3S7TaGLd/wM1ec7nCOgOKQAAAABJRU5ErkJggk==
由几何关系可得:平行斜面分量为iVBORw0KGgoAAAANSUhEUgAAAJAAAAAwCAYAAAD+WvNWAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAJcEhZcwAAHsIAAB7CAW7QdT4AAATTSURBVHhe7ZqNUSMxDEbTDF3QBDXQAi3QAR1Q
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JaBiihJQMcF+/wGxEqRNNSTS6AAAAABJRU5ErkJggk==
,由于引桥越长,坡角iVBORw0KGgoAAAANSUhEUgAAABAAAAAnCAYAAAAGjMh0AAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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84uA4HrjjXRHUfApVVAFIiIPJE5c2EYE3xQAAAAASUVORK5CYIJ=
越小,iVBORw0KGgoAAAANSUhEUgAAAB4AAAAwCAYAAAAGlsrkAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAJcEhZcwAAHsIAAB7CAW7QdT4AAAFdSURBVFhH7ZZbDYQwEAAxgwtMoAELWMABDlCA
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ezyaamRexLK4iCsbgjexfp2ubB7exKDrfDZqr2K+NNIZSRy9z17FUJbl2iEjp/b7BJgN/TFxidn7
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a6LYK1Gs8S5mA5FASsi53u28i0XmCuGnU31EFAcjioPxJ7ExH4X3vqxTMfRhAAAAAElFTkSuQmCC
越小,压力变大,故摩擦力变大,但增加摩擦不是目的,故ABC错误,D正确。名师点评:本题关键将重力正交分解后,根据平衡条件求解出压力和重力的下滑分量,然后对结果联系实际情况讨论即可判断。5、答案:A【详解】拉力F产生两个效果(如图所示),iVBORw0KGgoAAAANSUhEUgAAA3kAAAIxCAMAAADHUoFSAAAABGdBTUEAALGPC/xhBQAAACBjSFJN
AAB6JgAAgIQAAPoAAACA6AAAdTAAAOpgAAA6mAAAF3CculE8AAADAFBMVEUAAAABAQECAgIDAwME
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tpxySRDzDPLEpK/uNPEBMrk0CHkGeULCw23mCoC8zAsAyxdSAOQJCQ+3mSsA8jIvACxfSAGQJyQ8
3GauAMjLvACwfCEFQJ6Q8HCbuQIgL/MCwPKFFAB5QsLDbeYKgLzMCwDLF1IA5AkJD7eZKwDyMi8A
LF9IAZAnJDzcZq4AyMu8ALB8IQVAnpDwcJu5AiAv8wLA8oUUAHlCwsNt5gqAvMwLAMsXUgDkCQkP
t5kr8P/GXiTJ8tRMegAAAABJRU5ErkJggk==
由题意可知绳子与水平方向的夹角正弦值为sin α=iVBORw0KGgoAAAANSUhEUgAAACUAAABYCAYAAAByIj4cAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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AABJRU5ErkJggk==
=0.1,所以绳子的作用力为F绳=iVBORw0KGgoAAAANSUhEUgAAAEEAAABYCAYAAACqLpoWAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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ANILoNaWkfIBAAAAAElFTkSuQmCC
=1 500 N,A项正确,BCD项错误.故选A.名师点评:考查如何进行受力分析及掌握力的平行四边形定则的应用,理解几何关系的运用.注意边长之比与力之比的关系.6、答案:C根据平行四边形定则,已知一个分力沿水平方向,做出平行四边形如图所示,iVBORw0KGgoAAAANSUhEUgAAAP0AAABFCAIAAAAOznezAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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Sirx+cXBY1Sjr+1TBa2A0fBtHEjAh0N858GuDa+DcCO/8MFSGUmSVXRg0KVydcVvydrFfrh4gH32
7XqHbq0bJyBi2DkfTvTNOJD4WkSXkUgoTv4eFA+6hwQEMJAGbrz9r0u3PtqxYA2E9cTdgkY3vB56
YM3l2x5HNwyv8OMv4fNIuCJBeX17DsV2Hxw81ADCHf3sArwM18EGBRu0i6hGo9DtgPLifniaHYv8
n0v734KkorDVPSgeJ0eAavoCY+KDz2Jb90EoIv50Ghx8epw4b8BORFSBppVwWateEtjpz2qz7MAm
uBVuLS5N5DqKJOWEk7/PAyJTCstTLOUG8GLmBEVwxtP8Ki8vrO3ZuHPCtPYpKSdy0j0qxqwbQFxl
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5jlz5sBS6l5SWYC/z2Qy/we0WF6THxUIdAAAAABJRU5ErkJggk==
由图形可知另一个分力F2的大小为: H4sIAAAAAAAEC6VVXWhcRRQ+Z+bebXPvyiZpSpO1PzdSoxCbbjallNIg201WfcgSslsEwSzreu2u
JJuQjcS8RQIhKpJSX0r7VhRafFIISPQhhVIfaot9KHkRDKIvPpWwYPEvfmfuTdIsVpTO7sw9c+bM
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PZTm1UoojZJnBaujdKhpD+z+CJAwBjgc4ttkDgaLQK8oDvmodqlP3+ay/oRX9IjqsM4BR3qZnrfK
dFPPq8/Rc/oGn9b3ebdvF/lLJ2Cf5R9CqUudcbc8urotLbc2si47H/Evzhifcf/kK+45Wm6VXqbr
bpkybpfqQ7/vLPBXzqVdrE1yPiUMbSrPr9kHIf2uPMRW2oXgkIqa85Vxv+Zl/RlvZGK8WKXv19pp
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f8Q8pR7gg4P2N/Z+0LeUBgAA
,故C正确,ABD错误。故选:C。名师点评:力的合成与分解都遵守平行四边形定则,根据平行四边形定则,做出图形即可求得分力的大小.7、答案:A把力F分解如图:iVBORw0KGgoAAAANSUhEUgAAAMoAAACYCAIAAAAqQeEDAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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等腰三角形的顶角为θ,由图可知,两分力对称相等,设分力为T,则: H4sIAAAAAAAEC6VTTWgTURCe93aTJmlkE6tYi9hEUBHtDzl4EIJs00ZFIsEEBC9JjGtdSDZttxJz
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,故A正确,BCD错误。故选:A。8、答案:C已知重力和两个分力的方向,根据平行四边形定则作力图,如图所示,iVBORw0KGgoAAAANSUhEUgAAAKMAAACDCAYAAADhwKu2AAAABGdBTUEAALGPC/xhBQAAAAlwSFlz
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vLESKfM3EiTREaKybzK9XLZTJxIJhgt0HfFMGLY5a2npvGlYeeOodtLKx+BnCAQn0qnMMbDIWdPS
C4XxnG3mE6VLxnRu1rAR9m8tzrDU/tywP1G6Nmcac6JyEfalMtrk9fm5HNpIm0ACL1+vfaIW644O
HWlmo0vRoWRWn272H9Cnnd2qDmfSOeQsjWdJC6kJ+mv2aw+bMtmiZCCrOuXscZbI3pedyE464qer
CqPwMU6LgsiodiXa+6gbZdZpUaiM40YSKvn2AT3MNSyOgCz0gkxuXz2OuHuI1GcDDY4Fm/AWTCEs
EotjQgxTu9dXsELGOIHRECGEzWiePkopcMEA0agiG7I7UdyqWp8g5HJXp7O9ygihy7U+FnOjTjcb
SFfteaMIiCkgEGO47QKJGaV87HU7apBJ650lKg/4DRQGJ9I8BQAA
,故选C.名师点评:已知合力和两个分力的方向,根据平行四边形定则作力图,然后解矢量三角形.9、答案:B将人所受的重力按照效果进行分解,由于大小方向确定的一个力分解为两个等大的力时,合力在分力的角平分线上,且两分力的夹角越大,分力越大,因而D图中人最费力,B图中人最省力;故选B.名师点评:本题中人受到三个力,重力和两个拉力.将重力按照力的效果分解,运用“大小方向确定的一个力分解为两个等大的力时,合力在分力的角平分线上,且两分力的夹角越大,分力越大”的结论,即可以判断.10、答案:DA.F1不是物体对斜面的压力。因为物体对斜面的压力受力物体是斜面,而F1的受力体是物体。故A错误;B.物体对斜面的压力方向垂直于斜面向下,与F1的方向相同,根据几何知识得到,F1=Gcosα.故B错误;C.F2不是物体受到的静摩力,而使物体下滑的力,大小等于物体受到的静摩力。故C错误;D. 物体受到重力和斜面对物体的作用力而处于静止状态,所以物体受到的重力和斜面对物体的作用力是一对平衡力,故D正确。故选:D。11、答案:C将人所受的重力按照效果进行分解,由于大小方向确定的一个力分解为两个等大的力时,合力在分力的角平分线上,且两分力的夹角越大,分力越大,因而C图中人最费力,AD图中人最省力;故选C.名师点评:人受到三个力,重力和两个拉力.将重力按照力的效果分解,运用“大小方向确定的一个力分解为两个等大的力时,合力在分力的角平分线上,且两分力的夹角越大,分力越大”的结论判断.12、答案:A减小斜面倾角,则汽车的重力沿斜面向下的分力也减小,保证行车方便和安全,故A正确.小孩的重力只与小孩的质量和重力加速度有关,与滑梯坡度无关,故B错误.运动员手臂的合力大小一直等于其重力,手臂夹角增大时,为了保证合力不变,手臂上的力要增大,故C错误.设劈背的宽度是d,劈的侧面的长度是L,将作用在劈背上力F分解为H4sIAAAAAAAEC41SO2hTYRT+zp+HzU3gJlWxVjE3inWxqQ3UOWke1SESTEC3GOO1XsiLJFazRYSi
IkRw66agk7OTQycXH2sXB1HsLOEuYjGe8ydFqQqee+9/z+M/33luvXu9AU1Jb1JRQNjwZQIznpcE
KLzQVh+filgB4UiNRiPNxenwRBdUzGhdSCVV0htkac5vIoR8pXuj1GvZwBVMT7SzYIQRx2J5k7nn
InmBbQ4hEQKCpoQ7oD7TNxxl7ruy2EPokSQiyYVLTt3uWBfsW9bFZr3SwIetGfQfR9f6dGLt/tT1
JYbEPN82+J+Qg52AxcSG2qQxep9yE/T+D7ELuob/b3SSxPH1jyi53B0Fz26UFRrX8CsKO61LOm/e
v/0CznfHZ+x83O7+s4ZxFNpTy5On8EBPSbqdp1Sr1cnn0mnCHGckX8buOKsNq1h17EbVPm2db1Tj
8BH8gUwxXzoL2n/JaaRqteVKx6mmm9fsQmXV7iDi29vciKfYq19t1tiUbt5sO3ZbOo+IN1+ysre7
7QomSL+B+HV105iKLZwalmOD2MJKOVUYRo+lCu5BMwU36550B8tl5sJmmn/DqPVsaLAuxgrWmufc
Q+6A9bPlTDnrypsyQwR+FBM3kHheHpa9vDkG6ZWSMZqkcDcHk21HgCBpxb1FNrAHDDE/pDN/u5OY
3GEQWRnpq6H3lZvJNJ5jGPu09EoWap1zOV7sdbp2HUuyd+IZxwPtIEfo04zeknkOvbstPDamn2Gv
13CCAwAA
两个分力,且与劈的两个侧面垂直,根据对称性,两分力H4sIAAAAAAAEC41SO2hTYRT+zp9HzU3gJlWxVjE3inWxqc3gnNs8aodIMAHdYhqvNZAXSaxmiwhF
JBDBrZuCTs5ODp1cfKxdHESxs4S7iGA850+KUhU8997/nsd/vvPcffd6G5qS3qSigLDhawRmPC8J
UHihrT4+FbECwpEaj8eai9PxqS6omNG6kEqqpDfI0oLfRAi5cvdWsddygOuYnWrnwQhjjsXyDnPP
RfICexxCIgQETQl3RH2mbzjJ3HdlsYfQI0lEkgsXq3WnY1127lhXmvVyAx9259B/HN3s05nNxMzN
AUNikW8b/E/IwU7AcmJb7dAEvU/ZKXr/h9gFXcP/NzpJ4vj6R5Rs9p6CZz/KKk1q+BWFnbYknTfv
334B57vmNyIf97r/rGEShQ7U8uQpPNBTkm7nyG61OrlsKkVY4IzkSzud6kbDKlSqTqPinLfWGpU4
fAR/IF3IFS+CDl+tNuxabaXcqVZSzRtOvrzhdBDxHWxuxFPo1debNTalmrfbVactnUfEmytambvd
dhlTpN9A/Lq6WRyKLZ0blWLD2NJqyc6PoqfsvHvUtOFm3LPucKXEXNhM8W8UtZ6NDNbFWMFa85J7
zB2yfr6ULmVceW0zROBHMXEDieflYdnLm2OQXikZo0kK97Mw2XYCCJJWPFhmA3vAEPOALvztTmJ6
h0FkZaSvht5XbibTZI5hzGjplSzUFudyutDrdJ06BrJ34hnHQ+0gR+jTnN6SRQ69vy08NqafagwS
h4IDAAA=
大小相等,则以H4sIAAAAAAAEC41SS2gTYRD+5k9SzQM2qYq1itko1otNbRDP2eZRPUSCCegtxrjWhbzIxmpuEaGI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为为邻边的平行四边形就是一个菱形,如图所示:iVBORw0KGgoAAAANSUhEUgAAARMAAACbCAYAAABBPX+5AAAAAXNSR0IArs4c6QAAAARnQU1BAACx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gC4yQVRdryZIzsLrp8tZOUtaSCaB0lcgJlzQnBO2C11ksuikQuUsaSGZBIQLgdh0XZKgi0xcLnfA
8yhniRvJZGR8CMSka/XQVia8bmTiA+UscSKZjIBvgZggki5LObaVSdfnXQTlLHEgmQzEkAIx6VpB
tJXJonlJX6blLJqxPD6SiUfGEogNf7/tJ3lbmbjMS/rC3zdzFnqWEBzLKYjhkUwcE4pATLosSdBG
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kMt7kQJUJuQsVCrKWRZHMmkgFYGY8PqpTuYxTya8L6HnJX3hPeJ/U87SD8mkIkWBmExbytFmnkxi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因为菱形的对角线互相垂直且平分,所以根据三角形相似: H4sIAAAAAAAEC6VUTWgTQRR+M7Mbmx/YxFasVcxG0YLYlObgreA2TfwhkWACnkoa07UG8tckRuNB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,解得: H4sIAAAAAAAEC7VUS2sTURT+7p28G5zE+qhV7KSibrSlWbjLIk0aFRoNJtJlGtOxDuRFJlbjKiAU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,在L、F不变的情况下,两个侧面之间的夹角越小,即d越小, H4sIAAAAAAAEC41SO2hTYRT+zp80NQ+4SVWsVcyNYl1sajM4J82jOkSDCeiWxnitF/IiN1azRYQi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越大,越容易钉进物体,故D错误;故选A.13、答案:B将一个大小为6N的力F沿相互垂直的x轴和y轴分解.力F与x轴的夹角H4sIAAAAAAAEC3VSTYjTUBCeeUmqzRbS+rsuYlNFRXC7RaG3gtm2/hy6FFvwsIdsrdk10KbdplZ7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,根据三角知识,则力F在x轴上的分力H4sIAAAAAAAEC5VSO4sTURQ+5+ahecAkPnBdFzNRXBHcLFhY72weahEJJmAlcTZedweSTMjENekG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的大小为: H4sIAAAAAAAEC6VUTWgTURCe93a3NpvIZq1iraXdKNaLTf8gtxzStFHBhGICHtMY1xrIH91Ym1uK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,故ACD错误,B正确.故选B.14、答案:DA、甲悬在空中静止,甲受到平衡力作用,绳子的拉力和甲的重力是一对平衡力,甲受到绳子的拉力等于甲的重力,故A错误;B、绳子对甲的拉力与甲对绳子的拉力是作用力和反作用力,大小相等,故B错误;C、甲乙质量相等,重力相等,绳子相同,甲悬在空中绳子未拉断,绳子的拉力等于甲的重力,乙拉住绷紧绳子的中点把绳子拉断了,绳子对乙的拉力大于绳子对甲的拉力,甲乙重力相等,所以乙拉断绳子前瞬间,绳受到的拉力一定大于乙受到的重力,故C错误,D正确;故选D。15、答案:B幼儿园的滑梯很陡,是为了增加小孩重力沿斜面方向的分力,使小孩下滑得更快,选项A错误;高大的桥要建很长的引桥,减小斜面的倾角,是为了减小汽车重力沿桥面向下的分力,达到行车方便和安全的目的,选项B正确;运动员做引体向上(缓慢上升)运动时,双臂张开很大的角度时要比双臂竖直平行时觉得手臂用力大,是因为合力不变,张开的角度越大时,分力越大,则手臂产生的力增大的缘故,选项C错误;两位同学提一桶水的时候,当两个分力角度大于一定角度时,分力会大于合力,选项D错误;故选B.名师点评:考查力的平行四边形定则的应用,及掌握如何进行分解.搞清分力与合力的大小关系.16、答案:B斜面上物体的重力,按效果分解的力图如题目图.根据数学知识可知F2=Gsinθ,F1=Gcosθ.故B正确,ACD错误;故选B.17、答案:C根据平行四边形定则,将绳中的拉力F沿水平和竖直方向分解,可得拉力F在竖直方向的分力iVBORw0KGgoAAAANSUhEUgAAAHIAAAAwCAYAAADNTS4aAAAAAXNSR0IArs4c6QAAAARnQU1BAACx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,故C项正确。18、答案:D将汽车对千斤顶的压力F分解沿两臂的两个分力F1,根据对称性可知,两臂受到的压力大小相等,即F1=F2.由2F1cosθ=F得F1=H4sIAAAAAAAEC6VTT2jTYBR/35emrl0h7aY4i6ypQ0XQbvTQs1n/OIVKsRXFS6wxzkCblKZ29lYY
jCGDCl7E0w4K4qlHD6I9eVDndRcPQ9CzlJwUrO8l6SaFgeAjeXl/8r3f+96f3Z33z8ClbXFPYCES
SzcZoCBMc4AAvHK9InLOGHKSGB+NRq6UYid8G/3teSN8T9gWp1E7E5QgAsVq636l09ABBjDjW+OA
EUYAUdQHKL3G9zaGfioATKHtJ0YjHxIPILuA0IR8lAO/6EqzKK2IZAsRMve8W8ItOInqL979jR+k
x5Q0+iFaMeq6LV/V1+RrVr1qwpfdOeg+SbS7bKGtzt875+EwzBggHaZDmAykM0vXP/ABKh6CyQp8
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TPjd3ve1Q+p12G36eBuaHZqBK0xpNOxiIZtlsIBXpTen28aqKZc1Qzc1/bx82dRSIDIIhnLlYiUD
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9Ajz3CwEAAA=
=F=1.0×105N 故AC正确.iVBORw0KGgoAAAANSUhEUgAAALEAAAB3CAYAAABMmKFsAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAJcEhZcwAADsIAAA7CARUoSoAAABnuSURBVHhe7d1ZjGVF/QdwXn0w0WeNPvii4cWo
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继续摇动把手,两臂靠拢,夹角θ减小,由 F1=H4sIAAAAAAAEC6VTzWsTURCf994mNmlgE6vYhmI2inrRFHLwnO0mUQ+RYAJ+XNK4rnUh2U2zMTW3
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分析可知,F不变,当θ减小时,cosθ增大,F1减小.故D错误,B正确.此题选择错误的选项,故选D.19、答案:A在拉开拉链的时候,三角形物体在两链间运动,手的拉力在三角形物体上产生了两个分力,分力的大小大于拉力的大小,所以很难直接分开的拉链很容易拉开,故A正确,BCD错误。20、答案:BF、F1、F2三个力恰好组成一个三角形,所以F2最小时应该是F2和F1相互垂直时,所以最小值为H4sIAAAAAAAEC41Sv2/TUBC+e3ZC41pyAkWUChEHBF1oWjGwu04CDEERicTAYEwwxVLipHEIZEoQ
qANLkJCQYEX8DwwMmbrwY+3CUCHBXFnekAh3r66oKpB4st/77t579927+3Y+b78BOUx1iphhuHcb
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,故B正确;综上所述本题答案是:B